A Cyclic Sum With a Twist

7/10PolynomialsinequalitySymmetry

Problem

Let a,b,c>0a, b, c > 0. Prove that

a(a2+bc)b+c+b(b2+ca)c+a+c(c2+ab)a+bab+bc+ca.\frac{a\left(a^2+bc\right)}{b+c} + \frac{b\left(b^2+ca\right)}{c+a} + \frac{c\left(c^2+ab\right)}{a+b} \ge ab + bc + ca.

Answer

Solution

Difficulty7/10
TopicsPolynomials, inequality, Symmetry

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