A Focal Triangle Area from a Bisector

8/10conic sections

Problem

The hyperbola C:x2y224=1C:x^2-\dfrac{y^2}{24}=1 has left and right foci F1F_1, F2F_2. Let PP be a point of CC in the first quadrant, and let ll be the bisector of F1PF2\angle F_1PF_2. The line through the origin OO parallel to PF2PF_2 meets PF1PF_1 and ll at points MM and NN respectively. If MN=23PF2|MN|=\dfrac 23|PF_2|, find the area of PF1F2\triangle PF_1F_2.

Answer

Solution

Difficulty8/10
Topicsconic sections

Whiteboard

Your sketch is saved only in this browser. To share it, export your drawing as an image (whiteboard menu → Export as → PNG), then upload that image in the comments below.

Discussion

Ask questions, share alternate solutions, and use LaTeX freely.

0 comments
Log in to join the discussion.

No comments yet.