Another Perpendicular-Bisector Dot Product

★ 5/10plane geometry Polarization Identity vectors

Problem

In $\triangle ABC$ , the perpendicular bisector of the side $BC$ meets $BC$ at $Q$ and meets $AC$ at $P$ . Given $\left|\overrightarrow{AB}\right|=1$ and $\left|\overrightarrow{AC}\right|=2$ , find $\overrightarrow{AP}\cdot\overrightarrow{BC}$ .

Answer

Solution

Difficulty	5/10
Topics	plane geometry, Polarization Identity, vectors

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