Vectors from a Centroid

Problem

A point OO in the plane of △ABC\triangle ABC satisfies

OA→+OB→+OC→=0→,\overrightarrow{OA} + \overrightarrow{OB} + \overrightarrow{OC} = \overrightarrow{0},

with ∣OA→∣=2|\overrightarrow{OA}| = 2, ∣OB→∣=3|\overrightarrow{OB}| = 3, ∣OC→∣=4|\overrightarrow{OC}| = 4. Let θ\theta be the angle between OA→\overrightarrow{OA} and OB→\overrightarrow{OB}.

1. Find cos⁡θ\cos\theta. 2. Find OA→⋅OB→+OA→⋅OC→\overrightarrow{OA}\cdot\overrightarrow{OB} + \overrightarrow{OA}\cdot\overrightarrow{OC}.

Answer

Solution

Difficulty6/10
Topicsplane geometry, Polarization Identity, vectors

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