A Cyclic Ratio Comparison

Problem

Let a1,a2,,an>0a_1, a_2, \ldots, a_n > 0 be real numbers. Prove that

i=1nai1aii=1nai1+ai+1ai+ai+1+1,\sum_{i=1}^n \frac{a_{i-1}}{a_i} \geqslant \sum_{i=1}^n \frac{a_{i-1} + a_i + 1}{a_i + a_{i+1} + 1},

where indices are cyclic: a0=ana_0 = a_n and an+1=a1a_{n+1} = a_1.

Answer

Solution

Difficulty8/10
TopicsSubstitution, inequality, Rearrangement Inequality

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