A Dihedral Circumsphere

The base of the tetrahedron $P\text{-}ABC$ is an equilateral triangle of side $2$. Given $PA = PB = \sqrt{2}$ and that the dihedral angle $P\text{-}BA\text{-}C$ measures $60^\circ$, find the circumradius $R$ of the tetrahedron $P\text{-}ABC$.