A Parallel Line Turns Tangent

7/10Parametrizationconic sections

Problem

The parabola C:y2=2pxC:y^2=2px (p>0p>0) has focus FF, and its directrix meets the xx-axis at a point DD. A line through FF meets CC at two points AA and BB, with

FAFB=FA+FB.|FA|\cdot|FB|=|FA|+|FB|.

1. Find the equation of the parabola CC. 2. Let PP and QQ be distinct points on CC with PFxPF\perp x-axis. The line PQPQ meets the xx-axis at a point GG, and a point EE is chosen on the xx-axis with GE=GD|GE|=|GD| and GG between EE and DD. Let ll be the line through QQ parallel to PEPE. Prove that ll is tangent to the parabola CC.

Answer

Solution

Difficulty7/10
TopicsParametrization, conic sections

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