A Product from Symmetry

★ 4/10algebraVieta's FormulasSymmetry

Problem

Real numbers a,b,c,da, b, c, d satisfy

(a+c)(a+d)=(b+c)(b+d)=3,a≠b.(a+c)(a+d) = (b+c)(b+d) = 3, \qquad a \neq b.

Find (a+c)(b+c)(a+c)(b+c).

Answer

Solution

Difficulty4/10
Topicsalgebra, Vieta's Formulas, Symmetry

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