A Riemann Function Sum

8/10functionsSymmetry

Problem

The Riemann function is defined on [0,1][0, 1] by

R(x)={1p,x=qp, gcd(p,q)=1, p>q,0,x irrational in [0,1] or x{0,1}.R(x) = \begin{cases} \dfrac{1}{p}, & x = \dfrac{q}{p},\ \gcd(p, q) = 1,\ p > q,\\[4pt] 0, & x \text{ irrational in } [0,1] \text{ or } x \in \{0, 1\}. \end{cases}

A function f(x)f(x) on R\mathbb{R} satisfies f(3x)+f(23x)=0f(3x) + f(2 - 3x) = 0, the function f(x+2)f(x + 2) is even, and f(x)=R(x)f(x) = R(x) for x[0,1)x \in [0, 1). Find

k=12025f(k4).\sum_{k=1}^{2025} f\left(\frac{k}{4}\right).

Answer

Solution

Difficulty8/10
Topicsfunctions, Symmetry

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