A Riemann Sum Limit

★ 6/10Limitscalculus

Problem

Evaluate

lim⁡n→∞∑k=1n1nsin⁡(2k−1)π2n.\lim_{n\to\infty}\sum_{k=1}^{n}\frac 1n\sin\frac{(2k-1)\pi}{2n}.

Answer

Solution

Difficulty6/10
TopicsLimits, calculus

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