A Shifted Radical Constraint

Problem

Let a,b>0a, b > 0 with

a+b2+8=4.a + \sqrt{b^2 + 8} = 4.

Find the minimum value of 3a+1b\dfrac{3}{a} + \dfrac{1}{b}.

Answer

Solution

Difficulty7/10
Topicsalgebra, Estimation, Cauchy-Schwarz, inequality

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