An Area-Doubling Line

★ 7/10Parametrizationconic sections

Problem

The ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 (a>b>0a>b>0) has left and right vertices A1A_1, A2A_2 and right focus FF, with ∣A1F∣=3|A_1F|=3 and ∣A2F∣=1|A_2F|=1.

1. Find the equation of the ellipse and its eccentricity. 2. Let PP be a moving point on the ellipse (not a vertex), and let the line A2PA_2P meet the yy-axis at a point QQ. If the area of △A1PQ\triangle A_1PQ is twice the area of △A2FP\triangle A_2FP, find the equation of the line A2PA_2P.

Answer

Solution

Difficulty7/10
TopicsParametrization, conic sections

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