An Endpoint Analysis

Problem

Let

f(x)=ln⁡(1+x)−ax1−x,f(x) = \ln(1+x) - \frac{ax}{1-x},

where aa is real.

1. When a=1a = 1, find the intervals of monotonicity of f(x)f(x). 2. If f(x)⩽0f(x) \leqslant 0 for all −1<x<1-1 < x < 1, find the range of possible values of aa.

Answer

Solution

Difficulty8/10
Topicscalculus, Monotonicity, inequality, Casework

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