Infinitely Many Multiples of Seven

8/10number theorysequences

Problem

A sequence {an}\{a_n\} satisfies a1=1a_1 = 1 and

an=an1+an/2(n2).a_n = a_{n-1} + a_{\lfloor n/2 \rfloor} \qquad (n \ge 2).

Prove that infinitely many terms of {an}\{a_n\} are divisible by 77.

Answer

Solution

Difficulty8/10
Topicsnumber theory, sequences

Whiteboard

Your sketch is saved only in this browser. To share it, export your drawing as an image (whiteboard menu → Export as → PNG), then upload that image in the comments below.

Discussion

Ask questions, share alternate solutions, and use LaTeX freely.

0 comments
Log in to join the discussion.

No comments yet.