A Three-Variable Maximum

★ 8/10trigonometryinequality

Problem

Let a,b,c>0a, b, c > 0 with

a2+b2+4c2=1.a^2 + b^2 + 4c^2 = 1.

Find the maximum value of

ab+2ca+32 bc.ab + 2ca + 3\sqrt{2}\,bc.

Answer

Solution

Difficulty8/10
Topicstrigonometry, inequality

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