Two Floor Sums Adding Up

8/10number theoryCountingSymmetry

Problem

Let aa and bb be coprime positive integers with a+b=2005a+b=2005. Let [x][x] denote the integer part of xx, and set

A=[2005×1a]+[2005×2a]++[2005×aa],A=\left[\frac{2005\times 1}a\right]+\left[\frac{2005\times 2}a\right]+\cdots+\left[\frac{2005\times a}a\right], B=[2005×1b]+[2005×2b]++[2005×bb].B=\left[\frac{2005\times 1}b\right]+\left[\frac{2005\times 2}b\right]+\cdots+\left[\frac{2005\times b}b\right].

Find A+BA+B.

Answer

Solution

Difficulty8/10
Topicsnumber theory, Counting, Symmetry

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