Two Perpendicular Focal Vectors

7/10Law of Cosinesconic sectionsvectors

Problem

The hyperbola C:x2a2y2b2=1C:\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1 (a>0a>0, b>0b>0) has left and right foci F1F_1, F2F_2. A point AA lies on CC and a point BB lies on the yy-axis, with

F1AF1B,F2A=23F2B.\overrightarrow{F_1A}\perp\overrightarrow{F_1B},\qquad \overrightarrow{F_2A}=-\frac 23\overrightarrow{F_2B}.

Find the eccentricity of CC.

Answer

Solution

Difficulty7/10
TopicsLaw of Cosines, conic sections, vectors

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