Counting Zeros of a Periodic Odd Function

5/10functions

Problem

The function ff is odd, defined on all of R\mathbb{R}, has period 33, and

f(x)=ln(x2x+1)for x(0,32).f(x) = \ln\left(x^2 - x + 1\right) \quad \text{for } x \in \left(0, \tfrac32\right).

How many solutions does f(x)=0f(x) = 0 have in [0,6][0, 6]?

Answer

Solution

Difficulty5/10
Topicsfunctions

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