A Cantor-Style Function

Problem

A function ff defined on R\mathbb{R} satisfies

f(x)+f(1x)=1,f(x)=2f ⁣(x5),f(x) + f(1 - x) = 1, \qquad f(x) = 2f\!\left(\frac{x}{5}\right),

and f(x1)f(x2)f(x_1) \leqslant f(x_2) whenever 0x1x210 \leqslant x_1 \leqslant x_2 \leqslant 1. Find

f ⁣(12022).f\!\left(\frac{1}{2022}\right).

Answer

Solution

Difficulty6/10
Topicsfunctions, Monotonicity, Functional Equations

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