A Diameter Circle and a Fixed Length

Problem

An ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 (a>b>0a>b>0) passes through the point P(62,12)P\left(\dfrac{\sqrt 6}2,\dfrac 12\right) and has eccentricity 22\dfrac{\sqrt 2}2. Let M(2,t)M(2,t) (t>0t>0) be a moving point, and let OO be the origin.

1. Find the standard equation of the ellipse. 2. Find the equation of the circle that has OMOM as a diameter and is cut by the line 3x−4y−5=03x-4y-5=0 in a chord of length 22. 3. Let FF be the right focus of the ellipse. The line through FF perpendicular to OMOM meets the circle with diameter OMOM at a point NN. Prove that the length of the segment ONON is a constant, and find this constant.

Answer

Solution

Difficulty7/10
TopicsCircles, conic sections, analytic geometry

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