A General Term from a Ratio Recurrence

7/10RecursionsequencesTelescoping

Problem

A sequence {an}\{a_n\} satisfies

an+1+an1an+1an+1=n(nN),\frac{a_{n+1}+a_n-1}{a_{n+1}-a_n+1}=n\qquad(n\in\mathbb N^{*}),

and a2=6a_2=6. Find the general term of {an}\{a_n\}.

Answer

Solution

Difficulty7/10
TopicsRecursion, sequences, Telescoping

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