A Law-of-Cosines System

8/10SubstitutionalgebraSymmetry

Problem

Let x,y,zx,y,z be positive numbers satisfying

{x2+y2+xy=3,y2+z2+yz=4,z2+x2+zx=7.\begin{cases}x^2+y^2+xy=3,\\ y^2+z^2+yz=4,\\ z^2+x^2+zx=7.\end{cases}

Find x+y+zx+y+z.

Answer

Solution

Difficulty8/10
TopicsSubstitution, algebra, Symmetry

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