A Log-Shift Refinement

9/10ExtremacalculusMonotonicityinequality

Problem

Let f(x)=(x1)exax+1f(x) = (x-1)e^x - ax + 1.

1. For a=0a = 0, solve the inequality f(x)0f(x) \leqslant 0. 2. Prove that for every a>0a > 0,

f(ln(1+a))<0.f\left(\ln(1 + a)\right) < 0.
  1. Restrict ff to the domain (t,ln(et+a))\left(t, \ln\left(e^t + a\right)\right) and let AA be its range. Find a necessary and sufficient condition (on tt) for A(,0)A \subseteq (-\infty, 0) to hold for every a>0a > 0.

Answer

Solution

Difficulty9/10
TopicsExtrema, calculus, Monotonicity, inequality

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