A Logarithmic Telescope

Problem

Let a>0a > 0 and

f(x)=ln⁡(1+ax)−2xx+2.f(x) = \ln(1 + ax) - \frac{2x}{x + 2}.

1. When a=12a = \dfrac{1}{2}, find the extreme values of f(x)f(x). 2. Discuss the monotonicity of f(x)f(x) on (0,+∞)(0, +\infty). 3. For n∈N∗n \in \mathbb{N}^*, prove that

222+3+223+3+⋯+22n+1+3⩽27+ln⁡3⋅2n−12n+1.\frac{2}{2^2 + 3} + \frac{2}{2^3 + 3} + \cdots + \frac{2}{2^{n+1} + 3} \leqslant \frac{2}{7} + \ln\frac{3\cdot 2^{n-1}}{2^n + 1}.

Answer

Solution

Difficulty8/10
TopicsExtrema, calculus, Monotonicity, Telescoping, inequality

Whiteboard

Your sketch is saved only in this browser. To share it, export your drawing as an image (whiteboard menu → Export as → PNG), then upload that image in the comments below.

Discussion

Ask questions, share alternate solutions, and use LaTeX freely.

0 comments
Log in to join the discussion.

No comments yet.