A Max Distance from a Median Condition

Problem

In ABC\triangle ABC, AMAM is the median to side BCBC (with MM on BCBC), satisfying AM=ABACAM=AB-AC, and BC=4BC=4. Find the maximum distance from AA to the line BCBC.

Answer

Solution

Difficulty7/10
Topicsplane geometry, Extrema, conic sections, AM-GM

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