A Parallel Segment Inequality

Problem

In △ABC\triangle ABC, A=120∘A = 120^\circ and DD is the midpoint of side BCBC. Points E,FE, F move along sides AB,ACAB, AC respectively with EF∥BCEF \parallel BC. Prove that

DE+DF⩾BD.DE + DF \geqslant BD.

Answer

Solution

Difficulty7/10
Topicsplane geometry, Law of Cosines, Completing the Square, AM-GM, inequality, vectors

Whiteboard

Your sketch is saved only in this browser. To share it, export your drawing as an image (whiteboard menu → Export as → PNG), then upload that image in the comments below.

Discussion

Ask questions, share alternate solutions, and use LaTeX freely.

0 comments
Log in to join the discussion.

No comments yet.