A Piecewise Polynomial Ladder

Problem

A function f(x)f(x) on (0,+)(0, +\infty) is defined piecewise: for n1<xnn - 1 < x \leqslant n (with nNn \in \mathbb{N}^*),

f(x)=(xn+1)(xn)n.f(x) = (x - n + 1)(x - n)^n.

Determine, with proof, which of the following are true:

1. f(x)f(x+1)0f(x)f(x+1) \leqslant 0 for all x>0x > 0; 2. for t>0t > 0: f(x)f(x) has exactly two zeros in (t,2t)(t, 2t) if and only if t(32,52)t \in \left(\dfrac{3}{2}, \dfrac{5}{2}\right); 3. there exist positive reals aa and x0x_0 such that f(x)<eaxf(x) < e^{-ax} for all x>x0x > x_0; 4. for 2t<52 \leqslant t < 5: f(x)f(x) has exactly two critical points in (2t4,t+1)(2t - 4, t + 1) if and only if t[83,258)(196,185)t \in \left[\dfrac{8}{3}, \dfrac{25}{8}\right) \cup \left(\dfrac{19}{6}, \dfrac{18}{5}\right).

Answer

Solution

Difficulty9/10
Topicsfunctions, Extrema, calculus, Estimation, Casework

Whiteboard

Your sketch is saved only in this browser. To share it, export your drawing as an image (whiteboard menu → Export as → PNG), then upload that image in the comments below.

Discussion

Ask questions, share alternate solutions, and use LaTeX freely.

0 comments
Log in to join the discussion.

No comments yet.