A Product Inequality Splits

Problem

Suppose that for every x[1,+)x \in [1, +\infty),

(ln2(ax)1)(exb)0.\left(\ln^2(ax) - 1\right)\left(\mathrm{e}^x - b\right) \geqslant 0.

Determine, with proof, which of the following are true:

1. if a(0,1e)a \in \left(0, \dfrac{1}{\mathrm{e}}\right), then beb \leqslant \mathrm{e}; 2. if a(0,1e)a \in \left(0, \dfrac{1}{\mathrm{e}}\right), then b>eb > \mathrm{e}; 3. if a[1e,e)a \in \left[\dfrac{1}{\mathrm{e}}, \mathrm{e}\right), then ab=eea^b = \mathrm{e}^{\mathrm{e}}; 4. if a[1e,e)a \in \left[\dfrac{1}{\mathrm{e}}, \mathrm{e}\right), then ba=eeb^a = \mathrm{e}^{\mathrm{e}}.

Answer

Solution

Difficulty7/10
Topicsfunctions, calculus, Logarithms, inequality, Casework

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