A Ratio of Integrals

★ 9/10LimitscalculusRecursion

Problem

Suppose C,L∈RC, L \in \mathbb{R} with L≠0L \neq 0 satisfy

lim⁡n→∞nC∫0π/2xnsin⁡x dx∫0π/2xncos⁡x dx=L.\lim_{n \to \infty} \frac{n^C \displaystyle\int_0^{\pi/2} x^n \sin x \, dx}{\displaystyle\int_0^{\pi/2} x^n \cos x \, dx} = L.

Find LL.

Answer

Solution

Difficulty9/10
TopicsLimits, calculus, Recursion

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