A Reciprocal-Arithmetic Family

Problem

A positive sequence {an}\{a_n\} satisfies a1=1a_1 = 1 and

an+2(an+1an)=an(an+2an+1),nN.a_{n+2}\left(a_{n+1} - a_n\right) = a_n\left(a_{n+2} - a_{n+1}\right), \qquad n \in \mathbb{N}^*.

Let Tn=a1a2+a2a3++anan+1T_n = a_1a_2 + a_2a_3 + \cdots + a_na_{n+1}, and suppose T12=4T_{12} = 4. Determine, with proof, which of the following are true:

1. {an}\{a_n\} is decreasing; 2. a2024=62029a_{2024} = \dfrac{6}{2029}; 3. there exists nn with Tn=43T_n = \dfrac{4}{3}; 4. i=1100ai>10\displaystyle\sum_{i=1}^{100} a_i > 10.

Answer

Solution

Difficulty7/10
TopicsArithmetic Progression, sequences, Estimation, Telescoping

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