A Right Angle at the Focus

Problem

Consider the parabola C ⁣:y2=2pxC \colon y^2 = 2px (with p>0p > 0). The line x−2y+1=0x - 2y + 1 = 0 meets CC at points AA and BB with ∣AB∣=415|AB| = 4\sqrt{15}.

1. Find pp. 2. Let FF be the focus of CC, and let M,NM, N be points on CC with MF→⋅NF→=0\overrightarrow{MF} \cdot \overrightarrow{NF} = 0. Find the minimum area of triangle MNFMNF.

Answer

Solution

Difficulty7/10
TopicsExtrema, conic sections, analytic geometry, Vieta's Formulas

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