A Strict Symmetric Bound

★ 8/10algebraAM-GMinequalitySymmetry

Problem

Reals a,b,ca, b, c satisfy a+b+c=1a + b + c = 1 and abc>0abc > 0. Prove that

ab+bc+ca<abc2+14.ab + bc + ca < \frac{\sqrt{abc}}{2} + \frac14.

Answer

Solution

Difficulty8/10
Topicsalgebra, AM-GM, inequality, Symmetry

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