A Telescoping Power Sum

Problem

An arithmetic sequence {an}\{a_n\} has its first term equal to its common difference, and its partial sums SnS_n satisfy S10=55S_{10} = 55. A sequence {bn}\{b_n\} satisfies b1=1b_1 = 1 and, for n2n \geqslant 2,

bn=2n1an12Sn.b_n = \frac{2^{n-1}a_{n-1}}{2S_n}.

If TnT_n denotes the sum of the first nn terms of {bn}\{b_n\}, find T100T_{100}.

Answer

Solution

Difficulty6/10
TopicsArithmetic Progression, sequences, Telescoping

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