A Vanishing Determinant

6/10algebraLinear AlgebraPolynomials

Problem

Let a,b,c,da, b, c, d be real numbers with abcd=1abcd = 1. Prove that

a2+1a2a1a1b2+1b2b1b1c2+1c2c1c1d2+1d2d1d1=0.\begin{vmatrix} a^2 + \dfrac{1}{a^2} & a & \dfrac{1}{a} & 1 \\[2pt] b^2 + \dfrac{1}{b^2} & b & \dfrac{1}{b} & 1 \\[2pt] c^2 + \dfrac{1}{c^2} & c & \dfrac{1}{c} & 1 \\[2pt] d^2 + \dfrac{1}{d^2} & d & \dfrac{1}{d} & 1 \end{vmatrix} = 0.

Answer

Solution

Difficulty6/10
Topicsalgebra, Linear Algebra, Polynomials

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