An Exponential-Log Growth

★ 7/10ExtremacalculusMonotonicityinequality

Problem

Let f(x)=eax−1+ln⁡(x+1)f(x) = e^{ax} - 1 + \ln(x+1).

1. If f(x)f(x) is increasing on (−1,+∞)(-1, +\infty), find the range of possible values of aa. 2. If 0<a⩽10 < a \leqslant 1 and x>0x > 0, prove that f(x)>2axf(x) > 2ax.

Answer

Solution

Difficulty7/10
TopicsExtrema, calculus, Monotonicity, inequality

Whiteboard

Your sketch is saved only in this browser. To share it, export your drawing as an image (whiteboard menu → Export as → PNG), then upload that image in the comments below.

Discussion

Ask questions, share alternate solutions, and use LaTeX freely.

0 comments
Log in to join the discussion.

No comments yet.