An Incenter Region Area

Problem

In △ABC\triangle ABC, AC=6AC=6, BC=7BC=7, cos⁡A=15\cos A=\dfrac 15, and II is the incenter. A point PP satisfies IP→=xIA→+yIB→\overrightarrow{IP}=x\overrightarrow{IA}+y\overrightarrow{IB} with x,y∈[0,1]x,y\in[0,1]. Find the area of the region traced by PP.

Answer

Solution

Difficulty7/10
Topicsplane geometry, Law of Cosines, Triangle Geometry, vectors

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