Approximating Functions to Order kk

6/10functionscalculusLogarithms

Problem

Let f(x)f(x) be defined on a domain DD, and let g(x)g(x) be a function different from f(x)f(x). If at some point x=ξx = \xi we have

f(ξ)=g(ξ),f(ξ)=g(ξ),    f(k)(ξ)=g(k)(ξ),\begin{aligned} f(\xi)&=g(\xi),\\ f'(\xi)&=g'(\xi),\\ &\;\;\vdots\\ f^{(k)}(\xi)&=g^{(k)}(\xi),\end{aligned}

where kk is a positive integer and f(k)f^{(k)} denotes the kk-th derivative, we call g(x)g(x) an order-kk approximation of f(x)f(x) at x=ξx = \xi. For example, the tangent line y=g(x)y = g(x) to f(x)f(x) at x=x0x = x_0 is an order-11 approximation of f(x)f(x) there.

1. Find an order-22 approximation of f(x)=x3f(x) = x^3 at x=1x = 1. 2. Let f(x)=lnxf(x) = \ln x and g(x)=ax+bx+cg(x) = ax + \dfrac{b}{x} + c with a,b,cRa, b, c \in \mathbb{R}. Can g(x)g(x) be an order-22 approximation of f(x)f(x) at x=1x = 1? 3. Let f(x)=ln(x+1)f(x) = \ln(x+1) and g(x)=axx+bg(x) = \dfrac{ax}{x+b} with a,bRa, b \in \mathbb{R}. Can g(x)g(x) be an order-22 approximation of f(x)f(x) at x=0x = 0?

Answer

Solution

Difficulty6/10
Topicsfunctions, calculus, Logarithms

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