Bounding a Logistic Sum

Problem

A sequence {an}\{a_n\} satisfies a1=12a_1=\dfrac 12 and

an+1=anan2(nN).a_{n+1}=a_n-a_n^2\qquad(n\in\mathbb N^{*}).

1. Prove that 1anan+121\leqslant\dfrac{a_n}{a_{n+1}}\leqslant 2 for all nNn\in\mathbb N^{*}. 2. Let SnS_n be the sum of the first nn terms of {an2}\{a_n^2\}. Prove that

12(n+2)Snn12(n+1)(nN).\frac 1{2(n+2)}\leqslant\frac{S_n}n\leqslant\frac 1{2(n+1)}\qquad(n\in\mathbb N^{*}).

Answer

Solution

Difficulty8/10
Topicssequences, Induction, Telescoping, inequality

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