Even-Type Quadratics

Problem

Suppose x1,x2x_1, x_2 are the two real roots of the quadratic equation x2+bx+c=0x^2 + bx + c = 0, and ∣x1∣+∣x2∣=2∣k∣|x_1| + |x_2| = 2|k| for some integer kk. Then the equation is called an even-type quadratic. For example,

x2−6x−27=0,x2−2x−8=0,x2+3x−274=0,x2+6x−27=0,x2+4x+4=0x^2 - 6x - 27 = 0,\quad x^2 - 2x - 8 = 0,\quad x^2 + 3x - \tfrac{27}{4} = 0,\quad x^2 + 6x - 27 = 0,\quad x^2 + 4x + 4 = 0

are all even-type quadratics.

1. Is x2+x−12=0x^2 + x - 12 = 0 an even-type quadratic? Justify your answer. 2. Let bb be an integer. Does there always exist a real number cc such that x2+bx+c=0x^2 + bx + c = 0 is an even-type quadratic? Justify your answer.

Answer

Solution

Difficulty5/10
TopicsQuadratic Equations, number theory, Absolute Value, algebra, Polynomials, Vieta's Formulas

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