Reversed Cyclic Fractions

★ 7/10Substitutionalgebrainequality

Problem

Let a,b,c>0a, b, c > 0 with a+b+c=3a + b + c = 3. Prove that

a2b+b2c+c2a⩽ab2+bc2+ca2.\frac{a^2}{b} + \frac{b^2}{c} + \frac{c^2}{a} \leqslant \frac{a}{b^2} + \frac{b}{c^2} + \frac{c}{a^2}.

Answer

Solution

Difficulty7/10
TopicsSubstitution, algebra, inequality

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