Moving Point Perpendicular to a Diagonal Plane in a Rhombic Prism

★ 7/10Extremasolid geometryvectors

Problem

figure

In the prism ABCD-A1B1C1D1ABCD\text{-}A_1B_1C_1D_1, the edge AA1AA_1 is perpendicular to the base plane ABCDABCD, and the base ABCDABCD is a rhombus with AB=2AB = 2 and ∠BAD=60∘\angle BAD = 60^\circ; also AA1=52AA_1 = \dfrac{5}{2}. Let PP be the midpoint of BCBC, let MM be a point on the edge AA1AA_1, and let QQ be a point moving over the quadrilateral ABCDABCD (interior and boundary), with Q≠PQ \neq P, such that PQ⊥PQ \perp plane AA1C1CAA_1C_1C. If the cosine of the angle between the skew lines PQPQ and B1MB_1M is 24\dfrac{\sqrt{2}}{4}, find the range of possible values of MQMQ.

Answer

Solution

Difficulty7/10
TopicsExtrema, solid geometry, vectors

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