Three Lines Through PP

Problem

Consider the parabola C ⁣:y2=2pxC \colon y^2 = 2px (with p>0p > 0). Through the point P(2,1)P(2, 1), lines l1l_1 and l2l_2 with slopes k1k_1 and k2k_2 meet the parabola at A,BA, B and M,NM, N respectively. When k1=2k_1 = 2, PP is the midpoint of ABAB.

1. Find the equation of the parabola CC. 2. If PMPN=PAPB|PM| \cdot |PN| = |PA| \cdot |PB|, prove that k1+k2=0k_1 + k_2 = 0. 3. If the line AMAM passes through Q(2,0)Q(-2, 0), prove that the line BMBM passes through a fixed point, and find its coordinates.

Answer

Solution

Difficulty7/10
TopicsParametrization, conic sections, analytic geometry, Vieta's Formulas

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