Three Radicals, One Equation

Problem

Solve over the reals:

2x2+x+5+x2+x+1=x2−3x+13.\sqrt{2x^2 + x + 5} + \sqrt{x^2 + x + 1} = \sqrt{x^2 - 3x + 13}.

Answer

Solution

Difficulty6/10
TopicsQuadratic Equations, Substitution, algebra

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