Two Chords, One Fixed Point

Problem

Fix the parabola y2=2pxy^2 = 2px and points A(a,b)A(a, b), B(−a,0)B(-a, 0) with ab≠0ab \ne 0 and b2≠2pab^2 \ne 2pa. For a variable point MM on the parabola, the lines AMAM and BMBM meet the parabola again at M1M_1 and M2M_2 respectively. Prove that, whenever M1≠M2M_1 \ne M_2 exist, the line M1M2M_1M_2 passes through a fixed point, and find that point.

Answer

Solution

Difficulty8/10
TopicsParametrization, conic sections, analytic geometry

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