Two Equal Cubes

4/10complex numbersalgebraSymmetry

Problem

Prove that for all real numbers a,b,ca, b, c,

((2abc)+(bc)3i)3=((2bca)+(ca)3i)3.\left((2a-b-c) + (b-c)\sqrt{3}\,\mathrm{i}\right)^3 = \left((2b-c-a) + (c-a)\sqrt{3}\,\mathrm{i}\right)^3.

Answer

Solution

Difficulty4/10
Topicscomplex numbers, algebra, Symmetry

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