Two Extremes of an Exponential

★ 7/10ExtremacalculusMonotonicityinequality

Problem

The function f(x)=e2x−ax2−1f(x) = \mathrm{e}^{2x} - ax^2 - 1 (for x∈Rx \in \mathbb{R}) has two extreme points x1,x2x_1, x_2.

1. Find the range of possible values of the real number aa. 2. Prove that

ae2x1+ae2x2>2e2x1⋅e2x2.a\mathrm{e}^{2x_1} + a\mathrm{e}^{2x_2} > 2\mathrm{e}^{2x_1}\cdot\mathrm{e}^{2x_2}.

Answer

Solution

Difficulty7/10
TopicsExtrema, calculus, Monotonicity, inequality

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