Two Telescoping Bounds

Problem

Let an=n(n+1)⋅2na_n = n(n+1)\cdot 2^n for n∈N∗n \in \mathbb{N}^*. Prove:

1. 3a1+4a2+⋯+n+2an<1\dfrac{3}{a_1} + \dfrac{4}{a_2} + \cdots + \dfrac{n+2}{a_n} < 1; 2. 4a1+5a2+⋯+n+3an<43\dfrac{4}{a_1} + \dfrac{5}{a_2} + \cdots + \dfrac{n+3}{a_n} < \dfrac{4}{3}.

Answer

Solution

Difficulty7/10
TopicsGeometric Progression, sequences, Estimation, Telescoping, inequality

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