Zeros, Monotonicity, and a Bound

Problem

Let f(x)=lnxe1xf(x) = \ln x - \mathrm{e}^{1-x} and g(x)=a(x21)1xg(x) = a\left(x^2 - 1\right) - \dfrac{1}{x}.

1. Determine the number of zeros of y=f(x)y = f(x), with justification. 2. Let

h(x)=g(x)f(x)+exexxex.h(x) = g(x) - f(x) + \frac{\mathrm{e}^x - \mathrm{e}x}{x\mathrm{e}^x}.

Discuss the monotonicity of h(x)h(x). 3. If f(x)<g(x)f(x) < g(x) holds for all x(1,+)x \in (1, +\infty), find the range of possible values of the real number aa.

Answer

Solution

Difficulty7/10
Topicscalculus, Monotonicity, Logarithms, inequality, Casework

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