A Centroid Condition

Problem

In triangle ABCABC, the sides opposite angles A,B,CA, B, C are a,b,ca, b, c. Given c=25c = 2\sqrt{5} and

2asinCcosB=asinAbsinB+52bsinC,2a\sin C\cos B = a\sin A - b\sin B + \frac{\sqrt{5}}{2}b\sin C,

let OO be the point with OA+OB+OC=0\overrightarrow{OA} + \overrightarrow{OB} + \overrightarrow{OC} = \overrightarrow{0}, and suppose cosCAO=38\cos\angle CAO = \dfrac{3}{8}. Find the area of triangle ABCABC.

Answer

Solution

Difficulty6/10
TopicsLaw of Sines, trigonometry, Law of Cosines, vectors

Whiteboard

Your sketch is saved only in this browser. To share it, export your drawing as an image (whiteboard menu → Export as → PNG), then upload that image in the comments below.

Discussion

Ask questions, share alternate solutions, and use LaTeX freely.

0 comments
Log in to join the discussion.

No comments yet.