A Circumcircle's Second Point

Problem

Let AA be the right vertex of the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1 (with a>b>0a > b > 0), and let PQPQ be a chord not through AA whose slope is a fixed constant kk. Prove that the circumcircle of △APQ\triangle APQ always passes through a second fixed point B≠AB \neq A, and find the coordinates of BB.

Answer

Solution

Difficulty9/10
TopicsParametrization, Circles, conic sections, analytic geometry

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